Why is compressed liquid enthalpy nearly equal to saturated liquid?

Liquids are nearly incompressible; enthalpy change with pressure at constant T: (dh/dP)_T = v - T(dv/dT)_P ≈ v for liquids (small and nearly constant). Pressure effect is small compared to temperature effect.

How accurate is the approximation h ≈ h_f(T) + vΔP?

Error 50 MPa) or near critical point, use compressed liquid tables. Pump inlet typically modeled as saturated liquid at condenser pressure.

How much work does the boiler feedwater pump consume?

Pump work W = v_f·(P_high-P_low)/η_pump. For Rankine at 10 MPa, condensing at 0.01 MPa, v_f=0.001 m³/kg, η=0.85: W = 0.001×(10000-10)/0.85 = 11.8 kJ/kg. Small vs turbine work ~1000 kJ/kg.

Compressed Liquid Enthalpy Calculator

Estimate compressed liquid enthalpy: h(T,P) ≈ h_f(T) + v_f(T)·(P-P_sat). Accurate approximation for water below critical point. Pump work W_pump = v_f·(P_out-P_in)/η_pump in Rankine cycle calculation.

2D stress state at a point. All stresses in MPa.

σx — Normal Stress X (MPa)

σy — Normal Stress Y (MPa)

τxy — Shear Stress (MPa)

⚙ Mechanical Note: Results are based on standard textbook formulas and ISO/AASHTO references. Always verify critical designs with applicable codes (ISO 898, AASHTO 1993, AISC, Eurocode 3) and a qualified engineer.

How to Use

Enter the values for the patient or scenario you are assessing. Estimate compressed liquid enthalpy: h(T,P) ≈ h_f(T) + v_f(T)·(P-P_sat). Accurate approximation for water below critical point. Pump work W_pump = v_f·(P_out-P_in)/η_pump in Rankine cycle calculation. Use the compressed liquid result to inform your clinical assessment.

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Frequently Asked Questions

Why is compressed liquid enthalpy nearly equal to saturated liquid?

How accurate is the approximation h ≈ h_f(T) + vΔP?

How much work does the boiler feedwater pump consume?