What are isentropic relations?

Isentropic (constant entropy) relations link pressure, temperature, and density for adiabatic, reversible processes: P/ρ^γ = constant, T ∝ P^((γ−1)/γ). Used for nozzles, diffusers, and ideal compressor/turbine stages.

What is a normal shock?

A normal shock is a strong compression discontinuity perpendicular to the flow. The flow is supersonic upstream and subsonic downstream. There is a sharp rise in pressure, temperature, and density, and a drop in total pressure.

How do I find post-shock conditions?

Ma_2 = √((Ma_1² + 2/(γ−1))/(2γMa_1²/(γ−1) − 1)). For Ma_1 = 2 in air: Ma_2 ≈ 0.577. Rankine-Hugoniot relations give the pressure, temperature, and density ratios.

Isentropic Flow Relations Calculator

Apply isentropic relations: P_2/P_1 = (T_2/T_1)^(γ/(γ−1)) = (ρ_2/ρ_1)^γ. Calculate normal shock conditions: downstream Mach Ma_2 = √((Ma_1²+2/(γ−1))/(2γMa_1²/(γ−1)−1)).

2D stress state at a point. All stresses in MPa.

σx — Normal Stress X (MPa)

σy — Normal Stress Y (MPa)

τxy — Shear Stress (MPa)

⚙ Mechanical Note: Results are based on standard textbook formulas and ISO/AASHTO references. Always verify critical designs with applicable codes (ISO 898, AASHTO 1993, AISC, Eurocode 3) and a qualified engineer.

How to Use

Enter the values for the patient or scenario you are assessing. Apply isentropic relations: P_2/P_1 = (T_2/T_1)^(γ/(γ−1)) = (ρ_2/ρ_1)^γ. Calculate normal shock conditions: downstream Mach Ma_2 = √((Ma_1²+2/(γ−1))/(2γMa_1²/(γ−1)−1)). Use the isentropic relations result to inform your clinical assessment.

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Frequently Asked Questions

What are isentropic relations?

What is a normal shock?

How do I find post-shock conditions?